Create an HLA Assembly language program that prompts for a value and then prints a particular number series based on that entered number. You should print out each number separated by an underscore. Each number should alternate, positive or negative from the prior number.
Here are some example program dialogues to guide your efforts:
Gimme data: 12
12_11_13_10_14_9_15_8_16_7_17_6
Gimme data: 3
3_2_4
In an effort to help you focus on building an Assembly program, I’d like to offer you the following C statements which match the program specifications stated above. If you like, use them as the basis for building your Assembly program.
SAMPLE C CODE:
------------------------
int start;
int amount = 1; /* the delta amount to add to each value as the code loops */
bool negative = true; /* are we adding or subtracting from the delta */
printf( "Gimme data: " );
scanf( "%d", &start );
int value = start;
for (int i = 1; i <= start; i++)
{
if (i != 1)
{
printf( "_" );
}
printf( "%d", value );
if (negative)
{
value = value - amount;
}
else
{
value = value + amount;
}
amount = amount + 1;
negative = !negative;
}
printf( "n" );
Save your work locally on your machine! Once you complete the test, you can upload the .hla file in the Quiz 1 File Upload Area.
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Create an HLA Assembly language program that prompts for a single integer value from the user and prints an triangular pattern like the one shown below. If the number is negative, don't print anything at all.
Here are some example program dialogues to guide your efforts:
Feed Me: 3
X
XX
XXX
Feed Me: -6
Feed Me: 5
X
XX
XXX
XXXX
XXXXX
In an effort to help you focus on building an Assembly program, I’d like to offer you the following C statements matches the program specifications stated above. If you like, use them as the basis for building your Assembly program.
SAMPLE C CODE:
------------------------
int i, j, n, space, x;
printf( "Feed Me:" );
scanf( "%d", &n );
// the top half of the arrow...
for( i = 1; i <= n; i++ ) {
space = n - i;
x = n - space;
for (j = 1; j <= space; j++) {
printf( " " );
}
for (j = 1; j <= x; j++ ) {
printf( "X" );
}
printf( "n" );
}
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