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Find the probability density function (pdf) of the sample statistics s.

INSTRUCTIONS TO CANDIDATES
ANSWER ALL QUESTIONS

Problem 1 a) In class we discussed that if x1, x2, . . . , xn is an iid sample from a normal population with expected value µ and variance σ2, then ns follows a chi- squared distribution with n− 1 degrees ofΣfreedom  (where s2  is tΣhe uncorrected

directly that this statement is true in a sample with n = 2 elements.

b) (optional) Assume that the statement above is true for a sample with

ks2

n = k elements, that is     (k)   follows a chi-squared distribution with k   1 degrees

of freedom for an arbitrary positive integer k 2.  Show that this implies that

(k+1)s2

 

  (k+1)

σ2

 

follows a chi-squared distribution with k degrees of freedom. (Here

 

2

(k)

 

2 (k+1)

 

denote the uncorrected sample variance calculated from a sample

 

with k and k + 1 elements, respectively.)

 

Problem 2 (Analytic derivation of the sampling distribution)

Let  X  be  a  uniform  random  variable  on  the  [0, 1]  interval.  Let  us  draw a random sample with n = 2 elements from this distribution: the sample is (x1, x2).

Define sample statistics s as the sum of the sample elements: s = x1 + x2.

a) Find the cumulative distribution function (cdf) of sample statistics s! (Hint: in order to calculate Fx1+x2 (a), you will have to calculate the probabilities P (x1 + x2 a).  For this, you can use the proof on page 55 of the presentation file “lecture1.pdf”(page title “Special properties / 3”), or you can use a geometric proof as well.)

b) Find the probability density function (pdf) of the sample statistics s.

 

Problem 3 We can extend the previous problem to the random sample with n = 3 elements, where we define sample statistics s as s = x1+x2+x3. A similar but much more tedious calculation shows that the cdf of sample statistics s is now (you do not have to derive these results!!!):

a) Fs(a) = P (s ≤ a) = 0 if a ≤ 0,

b) F (a) = P (s ≤ a) = a3  if 0 ≤ a ≤ 1,

c) F (a) = P (s ≤ a) = −a3 + 3a2 − 3a + 1 if 1 ≤ a ≤ 2,

d) F (a) = P (s ≤ a) = a3  − 3a2  + 9a − 7  if 2 ≤ a ≤ 3,

e) Fs(a) = P (s ≤ a) = 1 if a ≥ 3.

 Find the pdf of the sampling distribution of sample statistics s. Plot this pdf (i.e. when n = 3) together with the pdf that you found in the previous problem for the n = 2 case.

Problem 4 Suppose that random variable X is uniformly distributed on the

interval [0; B], so its probability density function is f (x) =  1  if 0 ≤ x ≤ B and

f (x) = 0 otherwise.  Then its cumulative distribution function is F (x) =  B   if

0 x B (and F (x) = 1 for x > B and F (x) = 0 for x < 0).  We know that

for this distribution, the expected value is E(X) = µ = B , and the variance is

V ar(X) = σ2 = B2 .

Let us draw an iid sample of size n from this distribution: x1, x2, . . . , xn . We would like to estimate µ = B , the expected value of X with two estimators:

M

µ^1 = x (the sample mean) and µ^2 = , where M  is the sample maximum,  i.e.

the largest element of the sample: M = max  x1, x2, . . . , xn  .

a) Find the cumulative distribution function (cdf) of the sampling distribu-

tion of M , i.e.  for each real number m find F (m) = Pr (M m).

b) Find the pdf of M , f (m), and calculate E(M ) and V ar(M ).

c) Find E(µ1), V ar(µ1), E(µ2) and V ar(µ2).

d) Are µ1 and µ2 unbiased estimators of µ? Are they asymptotically unbi- ased? Are they consistent?

e) According to the MSE-criterion, which estimator is better? Does this contradict to what we discussed in class, i.e. that µ1 is a BLUE for µ?

Problem 5 Let X and Y be  two  independent  Bernoulli(p)  random  variables with parameter 0.5 ≤ p ≤ 1. We have a random sample of size n from both distributions:   {x1, x2, . . . , xn} and  {y1, y2, . . . ,Σyn},  and  theΣtwo  samples  are

 

 

 

 

 

   

 

n q

i=1    i i . Show that p = 1 + 1 + xy − x − y

 

n n

is a consistent estimator of

 

n ^ 2 4 2 2

Problem 6 (Comparing estimators via simulating their sampling distributions) Suppose that X is a uniform random variable  on  the  [0, 1]  interval.  Let  us draw a random sample of n = 3 elements from this distribution: x1, x2, x3. Let

us define two sample statistics:  x =  x1+x2+x3 , and m = Median(x1, x2, x3).

a) Calculate E(x) and V ar(x).

b) The analytical derivation of E(m) might be difficult, but what do you think it can be? Why?

c) In Excel, draw 3000 different random samples of n = 3 elements, and calculate x and m for each of these samples.

d) From your 3000 observations on x and m, ”estimate” E (x) , V ar (x) , E(m) and V ar(m). Compare your estimates about E (x) , V ar (x) , E(m) to your an- swers in a) and b).

e) If you wanted to estimate the expected value of random variable X (i.e.

E(X)), which estimator would you prefer: x or m? Why?

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