function P=pressure(flowrate, viscosity, ODH, N, rho)
% ODH= pore size of the SNU
% N= no of pores of the SNU
%rho=density of the liquid
%gamma=surface tension of the liquid
%L=thickness of the membrane
gamma=72E-3;
L=0.85E-6;
%qppore=flowrate through a single pore
%v =velocity of the liquid
%3.6=conversion of ml/hr to ul/sec
%1E-9=ul/s to m3/s
%ODH=in micrometers
%V=flowateperpore/area(m/s)
qppore=flowrate/N;
v=(qppore/3.6*1E-9)/(pi*((ODH*1E-6/2)^2));
Pvis=(6*viscosity*pi*(1+(16/3*L)/(pi*ODH*1E-6)))*v/(ODH*1E-6);
Pkin=2.25*0.5*rho*v^2;
P=(Pvis+Pkin)*1E-5;
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% modified following Andreas Volk's latest modifications
% this code takes VOLUME fraction as input - try Andreas's code if you
% prefer mass fraction
% This version 20 Dec 2017.
function[rho,eta]=density_viscosity_glycerine_mix(fraction_glyc,T)
volume_glycerol=fraction_glyc;
volume_water=1-fraction_glyc;
% Calculations:
total_volume=volume_glycerol+volume_water;
volume_fraction=volume_glycerol/total_volume;
%density_glycerol=1277-0.654*T; % kg/m^3, equation 24
density_glycerol=1273.3-0.6121*T; % UPDATED following Andreas Volk’s suggestion
density_water=1000*(1-((abs(T-3.98))/615)^1.71); % UPDATED following A.V.'s suggestion
mass_glycerol=density_glycerol*volume_glycerol; % kg
mass_water=density_water*volume_water; % kg
total_mass=mass_glycerol+mass_water; % kg
mass_fraction=mass_glycerol/total_mass;
viscosity_glycerol=0.001*12100*exp((-1233+T)*T/(9900+70*T)); % equation 22. Note factor of 0.001 -> converts to Ns/m^2
viscosity_water=0.001*1.790*exp((-1230-T)*T/(36100+360*T)); % equation 21. Again, note conversion to Ns/m^2
a=0.705-0.0017*T;
b=(4.9+0.036*T)*a^2.5;
alpha=1-mass_fraction+(a*b*mass_fraction*(1-mass_fraction))/(a*mass_fraction+b*(1-mass_fraction));
A=log(viscosity_water/viscosity_glycerol); % Note this is NATURAL LOG (ln), not base 10.
viscosity_mix=viscosity_glycerol*exp(A*alpha); % Ns/m^2, equation 6
% Andreas Volk polynomial:
c=1.78E-6*T.^2-1.82E-4*T+1.41E-2;
contraction=1+(c.*sin((mass_fraction).^1.31.*pi).^0.81);
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